Python 刷Leetcode题库,顺带学英语单词(20)
Add BinaryGiven two binary strings, return their sum (also a binary string).[#67]The input strings are both non-empty and contains only characters 1 or 0 .Examples:Input: a = "11", b = "1"Output: "100
Add Binary
Given two binary strings, return their sum (also a binary string). [#67]
The input strings are both non-empty and contains only characters 1 or 0 .
Examples:
Input: a = "11", b = "1"
Output: "100"
Input: a = "1010", b = "1011"
Output: "10101"
题意: 给定两个二进制数字符串,求两者之和的二进制数字符串。
>>> binsum = lambda a,b : bin(int(a,2)+int(b,2))[2:]
>>> a = "1010"; b = "1011"
>>> binsum(a,b)
'10101'
>>> a = "11"; b = "1"
>>> binsum(a,b)
'100'
>>>
Sqrt(x)
Implement int sqrt(int x) . [#69]
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Examples:
Input: 4
Output: 2
Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.
题意: 求非负整数的平方根,结果只要保留整数部分(截尾法取整)
正常用法:
>>> import math
>>> math.sqrt(4)
2.0
# 或者:
>>> 4**0.5
2.0
牛顿迭代法:
>>> def Sqrt1(x):
r = x
while r*r>x:
r = (r+x/r)/2
return r
>>> Sqrt1(9)
3.0
>>> Sqrt1(3)
1.7320508075688772
>>> Sqrt1(2)
1.414213562373095
>>> Sqrt1(1.44)
1.2
>>> Sqrt1(0)
0
注:此方法适用于所有非负实数,截尾取整操作略。

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