背景：由于k8s集群节点较多，需要统计到不同命名空间下的pod数量和节点上的pod数量。

实现方法：基于python实现

ns上的pod数量：

#!/usr/bin/python
import commands
namespaces = []
pod_namespaces = []
status,output = commands.getstatusoutput("kubectl get namespace")
if status == 0:
    lines = output.split('\n')
    for i in range(0,len(lines)):
        ns = lines[i].split()[0]
        if ns == 'NAME':
            continue
        namespaces.append(ns)
else:
   print("command is not found")
   exit()

sts,outp = commands.getstatusoutput("kubectl get pod -A")
line = outp.split('\n')
for i in range(0,len(line)):
    pod_ns = line[i].split()[0]
    if pod_ns == 'NAMESPACE':
        continue
    pod_namespaces.append(pod_ns)
for i in range(0,len(namespaces)):
    ns = namespaces[i]
    ns_num = pod_namespaces.count(ns)
    print (ns,ns_num)

node上的pod数量：

#!/usr/bin/python
import commands

nodes = []
node_pod = []
status,output = commands.getstatusoutput("kubectl get nodes")
lines = output.split('\n')
for i in range(0,len(lines)):
    node = lines[i].split()[0]
    if node == 'NAME':
        continue
    nodes.append(node)

sts,outp = commands.getstatusoutput("kubectl get pod -A -o wide")
line = outp.split('\n')
for i in range(0,len(line)):

    node = line[i].split()[7]
    if node == 'NODE':
        continue
    node_pod.append(node)
for i in range(0,len(nodes)):
    ns = nodes[i]
    num = node_pod.count(ns)
    print ns,num